If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9t^2-36=0
a = 9; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·9·(-36)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*9}=\frac{-36}{18} =-2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*9}=\frac{36}{18} =2 $
| x/2+1/5-x/6=3x/10+8/15 | | 19x+15=72 | | 3•(x+5)=69 | | 4(k+4)+13(k-1)=-3(k-3)+14 | | 6x+5-2x=20 | | 10=8+p | | 56+x=2x+28 | | x-x/3=2x-2/3 | | 3(v-8)+2(v+5)=7(v-4) | | -4x+8x-9=4x-16-5 | | 56+x=2x+14 | | 54+x=2x+14 | | 2x+3x=3x+1 | | (x^2+x+1)(x^2-x+1)=0 | | 5x+4/8x+5=34 | | 3x+3-2x-1=5x-5 | | -15p-6(2-4p)=4(p-6)-38 | | y÷5+2=6 | | 9x^2+42x+49=9x^2+42x+64 | | 8(z-3)-z=5z-17 | | 8(z-3)-2=5z-17 | | 1/2x+2/x^2=7/6x | | 3x/4-5=1/2 | | Y=62x | | (x+56)=x+(x*0.25) | | 17.5x4x=-6.5(3x-6) | | 2x-2(x-1)+5=4-3(x-1) | | (x+56)=(x+(640*0.25)) | | 2(6x+4)-6+2x=3x(4x+3)+1 | | x+7.8=9.8 | | 10-5x+2=10x+5-11x | | 2x+8-9x=7+2x-9 |